3500 divided by 4 This is a topic that many people are looking for. cfcambodge.org is a channel providing useful information about learning, life, digital marketing and online courses …. it will help you have an overview and solid multi-faceted knowledge . Today, cfcambodge.org would like to introduce to you 4th Grade GoMath – 4.5 – Estimate the Quotient Using Compatible Numbers. Following along are instructions in the video below:
Next lesson is estimating the quotient using compatible numbers. We need to know what compatible compatible numbers are in order to be able to do this lesson so let’s a look at compatible numbers compatible. Numbers are numbers that are easy to compute mentally.
So when we’re thinking about compatible numbers. If we’re thinking about multiplication. Those would be things like 7 times.
5. Which would give us 35 or we would have something like 9 times. 3.
That give us 27. Those are our basic facts things that we can solve really easily. When we’re thinking about the vision compatible numbers are our basic facts numbers that we can solve really easily.
So something like 14. Divided by 7. That would be a basic fact that would be something that was compatible that we can solve by just thinking about it really quickly.
We could also have something like 36 divided by 6 would give me 6 compatible numbers would be when our divisor goes into our dividend evenly when we can take our dividend and break it into even pieces without having anything left over now the title of our lesson is estimating the quotient using compatible numbers. When we were doing multiplication and we were estimating our product. We would see something like 217 times.
4. And so what we would do was round our number first. So.
We had around 2 200. And multiplied times. 4.
To make this problem. Easier for us to solve also to give us an idea of if we’re in the right range for our answer. When we’re estimating our quotient.
We’re going to do things a little bit differently. We’re going to use compatible numbers to help us if we see a problem like 371 divided by 5. I don’t want to round what i want to do is think about my compatible numbers.
And think about my facts my basic facts that i know so i’m gonna underline my first two numbers whatever two numbers are in my greatest place values and i’m going to think about my divisor and i’m going to think what facts do i know what does. 5 go into evenly what can i split 37 or a number close to 37 into evenly 5 times well 37 does not. 5.
Does not go into 37 evenly. But it does go into 35 evenly so i’m going to take this number of 371 and i’m going to change it to something that’s compatible with my 5. I want these numbers to be easy for me to divide.
And this is gonna give me an idea of if my actual quotient is in the right range or not so i would take my 371 and i would think about my two numbers in my greatest place value and think about my divisor. And what’s a compatible fact that i know 350 divided by 5. That gives me a basic fact that i know right here.
These are compatible with each other. And that would give me a quotient of 70. That means 355 split into five equal groups would give me 70 in each group this would be my estimate.
My estimate would be 70. Now if you thought about maybe you didn’t think about 350. But you thought about 400 you could have thought about 400 divided by 5.
They also have a basic factor. 8. There or compatible numbers in the 40 5 goes into 40 80 times or five goes into 480 times.
That means if we took 400 and split it into five equal groups. We would have 80 in each group either of these estimates would be fine. They would sandwich our actual quotient.
But either of these answers are using compatible numbers to solve let’s take a look at a problem like this. We already have compatible numbers here. We did this lesson.
A few lessons ago. So i wanted us to remember what we’re doing when we see something like this we’re gonna underline our basic fact so we have 9 and 63 9 goes into 63 evenly i mean. 9.
Can break 63 apart into nine equal sections. How many times nine times. What gives me something that’s close 263 9 times.
7. And then i’m going to take the 0 right here and bring it on over here. So if i took 630 and split it into nine equal groups.
I would have 70 in each group. This has compatible numbers already so i don’t need to do anything with my numbers. My next problem i have 253 divided by 6.
I need to find compatible numbers. So i’m gonna start by underlining my two numbers in my greatest place value and i’m gonna annoy my divisor and i need to think does 25 split evenly into 6 groups or i can think about it as 6 multiplied times anything to give me 25 well no it doesn’t but i can think about my 6 facts i can think about my multiples of 6 does. 6.
Go into anything that’s close to 25 sure it goes into 24. So i’m gonna use compatible numbers. And i’m going to change my 253 into 240 divided by 6.
When i do that my compatible numbers allow me to get an estimate i’m not rounding. I’m looking for things that are compatible. My numbers that my divisor will go into evenly or my dividend will spread out and equally separate into six equal groups in this case.
So now i can find my basic fact. I have my 24 and i have my six 6 goes into 24 four times evenly and then i have my extra zero right here that i can bring on over and so my estimate would be 40. I want you to try this problem underline your two numbers.
The greatest place values and think about your eight. What’s a basic fact a compatible fact that you can think that 8 goes into evenly or that you can split up into eight equal groups if i’m looking at 79. And i have a divisor of 8.
There’s not anything that i see with my 79. But how about if one up by one number 280. That is a compatible number.
So i can take my 795 and change this to 800 divided by 8. And this is going to be a basic fact a compatible number that i can divide into evenly eight and eight well eight divides into 8. One time and then i have two zeroes left over so my estimate would be 100.
Maybe you didn’t think about that though maybe you thought about 720 or 72. Because you knew that. 9 went into 72 or 8.
Went into 72 evenly and it went in 9 times. 90. Would also work as an estimate which one is closer.
Though this 100 is a lot closer to our actual quotient. This 800 is a lot closer to our dividend that we’re starting with so i would go with my 800. If i want a closer quotient next problem.
We have 2150 3 4. Underline. Those two greatest place values.
What’s a compatible number that you could change 2153 to i could change it to 2000. When i underline my two numbers and my greatest place value i have 21 4. Does not go evenly into 21.
But it does go evenly into 20. So i would change 2153 into 2000. And then i’d divide by 4 4.
Goes into 2000 or 20 rather 5. Times and then i have my two zeros that i can bring on over so i’d have 500 as my. Estimate that’s my closest estimate maybe you thought about 2400.
Divided by 4 you could have thought about that if you looked at your compatible. Numbers there this would have given you an estimate of. 600 we have 3700.
1. 5. Underline your two greatest place values.
And think about your patt herbal. Numbers. I have 37 and five five does not go evenly into 37 or 37.
Does not break evenly into five equal groups. So what number does that’s close to 37 well 35. Does so i have 35 and then i have 2 more place.
Values i’m going to cover with zeros so 3500. Divided by 5. That is a compatible.
Fact. 35. And 5 5.
Divides evenly into 35 7. Times. And that have my two zeroes.
I would bring over this would be a reasonable quotient for me maybe. I didn’t think of 3500 and instead. I thought of 4000 divided by 5.
I could have thought about this as well i’d have 40 and 5 5. Goes into 40 eight times and then i’d have my two zeros that bring over so another reasonable quotient would be 800 my actual quotient is going to fall between those two values. Let’s take a look at some word problems.
How could we apply this our car. Travels 187 miles in 3 hours about how far does the car travel each hour. One of the things i want us to notice about this problem is it does say about when we’re talking about about we don’t want the actual answer.
We just want an estimate now let’s think about this problem our car. We have a little car and it’s going from zero miles traveled all the way to 187 miles travel. And it’s doing that over the course of three hours.
Now. My problem is asking me about how far does it travel each hour. So if that’s three hours.
I would need to take my 187 and break it into three pieces. So this is a division problem. I’m going to take my 187 and divide it by three now because i want to know about how far does it travel each hour.
I’m going to use my compatible numbers to find an estimate. I’m going to underline my two numbers in my greatest place value and underline my three and i want you to think about this about how far does our car travel every hour well when we look at these two numbers. Our three does go into 18 evenly so that is a compatible number so instead of changing my 18.
All i’m going to do is make that ones place a zero. Now i have some compatible numbers that i can work with this makes it super easy for me to find my estimate three goes into 18. How many times six times and then i bring my zero over so about how far does it travel each hour about 60 miles and i use my compatible numbers to help me there our next word problem says a dog’s heartbeats 520 times.
In five minutes about how many times does a dog’s heart beat in one minute think about this problem. What are we going to do well it beats this many times 520 in five minutes. And i want to take that five minutes down to one minute so i’m going to be doing some division.
I also have my word about here. Which tells me i’m finding my estimate. So i’m going to divide 500 20 divided by five now.
I don’t want my actual answer. I want an estimate. So i’m going to use compatible numbers to help me i’m gonna underline my two greatest place values in my divisor five does not go into fifty two evenly.
But what does it go into evenly about how many times does a dog’s heart beat in one minute five goes into 50 evenly and i’d bring down my last place value. So i have five hundred five goes into five hundred 100 times. So my estimate would be about 100 beats per minute let’s take a look at one last problem logan and his three friends divide 171 pieces of halloween candy about how many pieces of candy will each person get all right what’s your division problem.
It tells us to divide. But what’s our division problem. We have logan and his three friends so we have a total of 4 people.
That we need to divide 171 by it tells me about so it’s asking me for my estimate. So i’d set up my problem 171 divided by 4 and then i’m going to use compatible numbers to find my estimate. I take my 17 and my 4 4.
Does not go evenly into 17. But it does go evenly into 16 and i’d use that to help me find about how many pieces each person is going to get. 4 goes into 16 4 times.
And i’d bring my zero over so each person would get about 40 pieces of candy ok takeaways from this lesson make sure we’re using compatible numbers underline those to place values in your divisor. The greatest or your dividend. The greatest place values and then think about can i split that into even groups.
However many even groups. My divisor is asking me for that’s our lesson for today tomorrow. We are going to start doing some long division see you then .
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